← The collection

Coupon Collector.

The final missing item can take much longer than the first few.

Interactive experimentintuitiveField note ·
Preparing the experiment…
THE SHORT VERSION

Coupon Collector, explained.

The coupon collector problem asks how many random draws it takes to obtain every type in a collection, including repeated draws of types already collected.

01 / THE MECHANISM

Why it happens

Early discoveries are easy because almost everything is new. Near completion, most draws are duplicates. With equally likely types, collecting all n types takes n times the harmonic sum on average, rather than merely n draws.

Collecting every equally likely type has a long tail because duplicates become common near completion.

Read the result

Watch the pace slow near the final missing type. Compare many collections: an average completion time does not promise that your particular collection will finish by that point.

02 / FOLLOW IT THROUGH

A worked example

Four equally likely stickers

  1. Each packet contains one of four sticker types, with equal probability.

  2. The expected time to complete the set is 4 × (1 + 1/2 + 1/3 + 1/4), about 8.33 packets.

  3. Once only one type is missing, each new packet has just a one-in-four chance of completing the set.

OPTIONAL DEEPER DETAILGo deeper: inside the model

Inside this model

Independent draws are uniform across the selected types. Exact expected draws to collect k types equal N times the sum of 1/(N-i) for i from zero to k-1. A seeded run shows one possible path.

03 / BEYOND THE EXPERIMENT

Where this idea is useful

A practical use

Planning how many random packs may be needed to complete a collection.

CHECK YOUR INTUITION

A common misconception

THE TEMPTING CONCLUSION

“Four types should take about four packets.”

THE MORE USEFUL DISTINCTION

That would require avoiding duplicates. Random sampling with replacement repeatedly spends draws on types you already have.

What this explanation leaves out

  • Real items may have different rarity and draws may not be independent.
ONE MORE QUESTION

What if one collectible is rare?

Unequal probabilities change the expectation. A rare final type can dominate the waiting time, so the equal-probability formula no longer applies.

TAKE THE IDEA WITH YOU

Which missing item could become the bottleneck in completing your collection or coverage?

Further reading

Explore the original research or the teaching reference behind this experiment.