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Kirchhoff’s Circuit Laws.

Balance a resistor bridge until no current crosses between its midpoints.

Interactive experimentintuitiveField note ·
INTERACTIVE EXPERIMENT / P07

Kirchhoff’s Circuit Laws

Balance a resistor bridge until no current crosses between its midpoints.

PLAY & EXPLAIN

Balance a Wheatstone-style bridge. A 12 V source feeds two divider branches: 10/20 Ω and 15/R Ω. A 10 Ω bridge joins the midpoints when connected.

560
12 V+ / −10 Ω15 Ω20 Ω15 Ω10 ΩSupply: 12 VGround: 0 V7.45 V6.62 V
Midpoint potentials relative to ground
Left midpoint7.45
Right midpoint6.62
Bridge current left → right (A)
0.0828
Source current (A)
0.8138
Return current (A)
0.8138
Balanced
No

Find R that makes midpoint current zero. Nodal equations enforce Kirchhoff current balance; ideal resistors and a constant source omit transient, thermal and measurement effects.

The circuit is ideal and steady. Transients, inductive fields, source resistance, thermal changes and measurement loading beyond the stated bridge resistor are absent.

THE SHORT VERSION

Kirchhoff’s Circuit Laws, explained.

Kirchhoff’s laws express current conservation at a circuit node and voltage balance around a closed loop under lumped-circuit assumptions.

01 / THE MECHANISM

Why it happens

Two resistor-divider midpoints are linked by ten ohms. Solving their two nodal equations yields midpoint voltages, bridge current and equal source and return currents; a lower-right resistance of thirty balances the bridge.

Kirchhoff’s laws express current conservation at a circuit node and voltage balance around a closed loop under lumped-circuit assumptions.

Read the result

At balance the midpoint potentials match, so connecting the bridge does not create midpoint current. Source and return currents still need not be zero.

02 / FOLLOW IT THROUGH

A worked example

Find the null in a resistor bridge

  1. Keep the fixed divider resistors at ten, twenty and fifteen ohms.

  2. Adjust the lower-right resistor to thirty ohms and inspect equal midpoint potentials.

  3. Open and reconnect the bridge, confirming zero cross-current at balance while the source still supplies the divider branches.

OPTIONAL DEEPER DETAILGo deeper: inside the model

Inside this model

Two resistor-divider midpoints are linked by ten ohms. Solving their two nodal equations yields midpoint voltages, bridge current and equal source and return currents; a lower-right resistance of thirty balances the bridge.

03 / BEYOND THE EXPERIMENT

Where this idea is useful

A practical use

Use a null measurement to compare resistance ratios without assuming every branch carries the same current.

CHECK YOUR INTUITION

A common misconception

THE TEMPTING CONCLUSION

“A zero bridge current means the entire circuit has no current.”

THE MORE USEFUL DISTINCTION

Equal midpoint potentials remove that branch’s driving voltage, while other complete branches can still carry current.

What this explanation leaves out

  • The circuit is ideal and steady. Transients, inductive fields, source resistance, thermal changes and measurement loading beyond the stated bridge resistor are absent.
ONE MORE QUESTION

Why solve nodal equations instead of adding all resistors?

The connected bridge is not a simple series chain; node balance accounts for how currents split and recombine.

TAKE THE IDEA WITH YOU

Which node or loop conservation statement constrains the quantity you want to infer?

Associated thinkers

Associated withGustav Kirchhoff ↗

Associations marked provisional are awaiting source review.

Further reading

Explore the original research or the teaching reference behind this experiment.