← The collection

Little’s Law.

More items in a stable process usually means a longer time spent inside it.

Interactive experimentintuitiveField note ·
Preparing the experiment…
THE SHORT VERSION

Little’s Law, explained.

Little's Law connects average work in a stable system, average throughput, and average time in the system: L = λW.

01 / THE MECHANISM

Why it happens

If items enter and leave at a stable long-run rate, spending longer in the system means more items are present on average. The relationship concerns averages over a consistent boundary, including waiting if waiting is inside that boundary.

In a stable queue, average inventory equals throughput multiplied by average time in the system.

Read the result

Compare the number of items in the system, the throughput rate, and the implied time. Keep units consistent and avoid treating a steadily growing backlog as a stable queue.

02 / FOLLOW IT THROUGH

A worked example

A team's open work

  1. A team completes eight tasks per week and has 24 tasks in progress on average.

  2. Little's Law gives an average time in the system of 24 ÷ 8 = three weeks.

  3. Reducing open work can reduce lead time if throughput and the system boundary stay comparable.

OPTIONAL DEEPER DETAILGo deeper: inside the model

Inside this model

W=L/λ, where L is average items in the system and λ is completed items per hour. The chart shows time for a range of average inventories at the chosen throughput.

03 / BEYOND THE EXPERIMENT

Where this idea is useful

A practical use

Use tickets in progress and tickets completed per day to estimate average response time.

CHECK YOUR INTUITION

A common misconception

THE TEMPTING CONCLUSION

“Every task will finish in exactly three weeks.”

THE MORE USEFUL DISTINCTION

The relationship describes averages. Individual tasks can vary widely, and changing the process can change throughput too.

What this explanation leaves out

  • The identity uses long-run averages in a stable system; a growing backlog cannot be summarized by one steady-state W.
ONE MORE QUESTION

Does the arrival rate always equal throughput?

In a stable system over a suitable observation period, they balance on average. If arrivals persistently exceed departures, the backlog grows and a stationary interpretation is inappropriate.

TAKE THE IDEA WITH YOU

Have you measured waiting and active work within the same boundary?

Associated thinkers

Further reading

Explore the original research or the teaching reference behind this experiment.